Session重叠问题学习 -最优化
发布时间:2022-04-04 10:23:43 所属栏目:MySql教程 来源:互联网
导读:这一周连续优化Session合并和拆分问题.每天都比前一天提升性能一倍以上. 终于在今天,用独创的小花狸Session合并算法达到了最优级别. 令人振奋的1.5秒到2秒级别. 时间已经很晚了,思路也有些不清晰了.先把代码贴出来.下周再仔细解释一下这个奇妙算法。 DELIM
![]() 这一周连续优化Session合并和拆分问题.每天都比前一天提升性能一倍以上. 终于在今天,用独创的小花狸Session合并算法达到了最优级别. 令人振奋的1.5秒到2秒级别. 时间已经很晚了,思路也有些不清晰了.先把代码贴出来.下周再仔细解释一下这个奇妙算法。 DELIMITER $$ CREATE DEFINER=`root`@`localhost` PROCEDURE `p`() BEGIN declare done int default 0; declare v_roomid bigint; declare v_time timestamp(6); declare v_cur_type smallint; declare v_before_roomid bigint default -1; declare v_before_type smallint default -1; declare v_before_time timestamp(6) ; declare v_num bigint default 0; declare cur_test CURSOR for select roomid,type,timepoint from tmp_time_point order by roomid,timepoint,type ; DECLARE CONTINUE HANDLER FOR NOT FOUND SET done = 1; drop table if exists t1; drop table if exists t2; drop table if exists tmp_time_point; drop table if exists tmp_result; drop table if exists tmp_min_range; CREATE temporary TABLE `t1` ( `roomid` int(11) NOT NULL DEFAULT '0', `userid` bigint(20) NOT NULL DEFAULT '0', `s` timestamp(6), `e` timestamp(6), primary KEY `roomid` (`roomid`,`s`,`e`,`userid`) ) ENGINE=memory; CREATE temporary TABLE `t2` ( `roomid` int(11) NOT NULL DEFAULT '0', `s` timestamp(6), `e` timestamp(6), primary KEY `roomid` (`roomid`,`s`,`e`) ) ENGINE=memory; CREATE temporary TABLE `tmp_min_range` ( `roomid` int(11) NOT NULL DEFAULT '0', `s` timestamp(6), `e` timestamp(6), primary KEY `roomid` (`roomid`,`s`,`e`), key(roomid,e) ) ENGINE=memory; create temporary table tmp_time_point( roomid bigint, timepoint timestamp(6), type smallint, key(roomid,timepoint) ) engine=memory; create temporary table tmp_result( roomid bigint, timepoint timestamp(6), c int ) engine=memory; SET @A=0; SET @B=0; insert into t1(roomid,userid,s,e) select distinct roomid, userid, if(date(s)!=date(e) and id>1,date(s+interval id-1 date(s+interval id-1 date(e) ,e,date_format(s+interval id-1 '%Y-%m-%d 23:59:59')) e from ( SELECT x.roomid,x.userid,s,e FROM ( ( SELECT @B:=@B+1 AS id,roomid,userid,s FROM ( SELECT DISTINCT roomid, userid, roomstart AS s FROM u_room_log a WHERE NOT EXISTS (SELECT * FROM u_room_log b WHERE a.roomid = b.roomid AND a.userid = b.userid AND a.roomstart > b.roomstart AND a.roomstart <= b.roomend) ) AS p ) AS x, ( SELECT @A:=@A+1 AS id,roomid,userid,e FROM ( SELECT DISTINCT roomid, userid, roomend AS e FROM u_room_log a WHERE NOT EXISTS (SELECT * FROM u_room_log b WHERE a.roomid = b.roomid AND a.userid = b.userid AND a.roomend >= b.roomstart AND a.roomend < b.roomend) ) AS o ) AS y ) WHERE x.id = y.id AND x.roomid = y.roomid AND x.userid = y.userid ) t1 , nums where nums.id<=datediff(e,s)+1 ; insert into t2 (roomid,s,e) select roomid, s+interval startnum/1000000 second s, e-interval endnum/1000000 second e from ( select roomid, s,e, startnum, when @eflag=eflag then @rn:=@rn+1 when @eflag:=eflag then @rn else @rn end endnum from ( select * from ( select when @sflag=sflag then @rn:=@rn+1 when @sflag:=sflag then @rn else @rn end startnum,roomid,s,e,sflag,eflag from ( select * from ( select t1.*,concat('[',roomid,'],',s) sflag,concat('[',roomid,'],',e) eflag from t1 order by roomid ,sflag )a,(select @sflag:='',@rn:=0,@eflag:='') vars ) b ) bb order by roomid,eflag ) c ) d ; insert into tmp_time_point(roomid,timepoint,type) select roomid,s,1 from t2; insert into tmp_time_point(roomid,timepoint,type) select roomid,e,0 from t2; insert into tmp_min_range(roomid,s,e) select distinct roomid,starttime starttime, endtime endtime from ( select if(@roomid=roomid,@d,'') as starttime,@d:=str_to_date(timepoint,'%Y-%m-%d %H:%i:%s.%f'),@roomid:=roomid,p.roomid,str_to_date(timepoint,'%Y-%m-%d %H:%i:%s.%f') endtime from tmp_time_point p,(select @d:='',@roomid:=-1) vars order by roomid,timepoint ) v4 where starttime!='' and date(starttime)=date(endtime); open cur_test; repeat fetch cur_test into v_roomid,v_cur_type,v_time; if done !=1 then -- 第一行或者每个房间的第一行 if v_before_roomid=-1 or v_roomid!=v_before_roomid then set v_before_roomid:=v_roomid; set v_before_type:=1; set v_before_time:='0000-00-00 00:00:00'; set v_num:=0; end if; if v_before_type=1 then set v_num:=v_num+1; insert into tmp_result(roomid,timepoint,c) values(v_roomid,v_time,v_num); end if; if v_before_type=0 then set v_num:=v_num-1; insert into tmp_result(roomid,timepoint,c) values(v_roomid,v_time,v_num); end if; set v_before_roomid:=v_roomid; set v_before_type:=v_cur_type; set v_before_time:=v_time; end if; until done end repeat; close cur_test; select roomid,date(s) dt,round(second,date_format(s,'%Y-%m-%d %H:%i:%s'),date_format(e,'%Y-%m-%d %H:%i:%s')))/60) ts,max(c)-1 c from ( select a.roomid,a.s,a.e,r.c,r.timepoint from tmp_result r inner join tmp_min_range a on( r.timepoint=a.e and r.roomid=a.roomid) where c>2 ) a group by roomid,date(s); END 和之前的算法比较,结果一致。基本上都在1.6秒左右. (编辑:丽水站长网) 【声明】本站内容均来自网络,其相关言论仅代表作者个人观点,不代表本站立场。若无意侵犯到您的权利,请及时与联系站长删除相关内容! |